<h3>Answer:</h3>
B) 10 pounds
<h3>Explanation:</h3>
Let x represent the amount of 70¢ candy to be added. The value of the mixture can be written as ...
... 90×30 + 70x = 85×(30+x) . . . . . where 30+x is the total weight of the mix
... 2700 +70x = 2550 +85x
... 150 = 15x . . . . . . add -70x-2550
... 10 = x . . . . . . . . . divide by the coefficient of x
10 pounds of candy at 70¢/lb must be added.
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Step-by-step explanation:
In this case, you input the value of y (y = 6) into the equation ( 2.5(y-x)= 0)
2.5(6-x) = 0
Open the bracket,
(2.5×6)-2.5x= 0
Collect like terms.
2.5x= 2.5×6
Divide both sides by the coefficient of x (2.5)
x = 6
So,
x= 6 is true.
.
Substituting 6 for x in the equation,
2.5(6-6)= 0
2.5•0 = 0
0= 0
Which is also true.
Repost your question. Unclear as typed.
Answer:
Carl's checked bags way 15.5 kilograms each.
Step-by-step explanation:
35-4=31 -> 31÷2=15.5
