Find the vertex and the axis of symmetry of the graph of the function
f(x)=3(x+1)^2
1 answer:
Answer: vertex (-1, 0) axis of symmetry -> x = -1
Step-by-step explanation:
f(x) =
to find the vertex do
x+1 = 0
to find the x value
x = -1
plug -1 into the equation
f(-1) =
f(-1) = 3(0)
f(-1) = 0
Therefore, the vertex is (-1, 0)
The axis of symmetry is
x = -1
because that is where the lowest x value is
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