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Neporo4naja [7]

1 year ago

7

Please help 4 math pages with questions. 1 has all the circle graphs, and all the other 3 have each circle graphs question. Plea

se help.

1 answer:

oksano4ka [1.4K]1 year ago

8 0

Answer:

Favorite chip Answers v

Step-by-step explanation:

1. How many were surveyed? 82+8+18+62=100

2. How many said Jalepeno was their favorite? 8/100 0r 2/25 or 8%

3. How many said BBQ was their favorite?62/100 or 31/50 or 62%

4. How would it effect your final answer if the percentages did not add up to 100%? This means that your percentages are wrong. In a circle graph the percentages always equal 100%!

5. Is it possible to determine a missing percentage in a circle graph? Yes, we can always assume the total percentage is 100 so you add your given percentages together and then subtract that total from 100 to find the missing percentage.

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Find the mean of this set of values<br>15 8<br>12 14 10 13<br>The mean value is:

AlekseyPX

Hey there!

Basically the mean is the average of your given set that you have!

Here is your formula:

mean = SUM of each over your terms DIVIDED BY NUMBER of terms

“15, 8, 12, 14, 10,13”

SUM = addition

15 + 8 + 12 + 14 + 10 + 13

15 + 8 = 23

23 + 12 + 14 + 10 + 13

23 + 12 = 35

35 + 14 + 10 + 13

35 + 14 = 49

49 + 10 + 13

49 + 10 = 59

59 + 13 = 72

72 / NUMBER OF TERMS

Number of terms: 6

72 / 6 = 12

Thus your answer your answer: 12 ☑️

Good luck on your assignment and enjoy your day!

~LoveYourselfFirst:)

5 0

2 years ago

What does 30 ≤ x + 10 ≤ 80 simplify to

MakcuM [25]

Answer:

20 ≤ x ≤ 70

Step-by-step explanation:

Given that:

30 ≤ x + 10 ≤ 80

By solving the left half inequality first:

30 ≤ x + 10

Subtracting 10 from both sides:

30 - 10 ≤ x + 10 -10

20 ≤ x

Now solving inequality of right half:

x + 10 ≤ 80

Subtracting 10 from both sides:

x + 10 -10 ≤ 80 - 10

x ≤ 70

So after simplification we get:

20 ≤ x ≤ 70

I hope it will help you!

4 0

3 years ago

A standard die is rolled. Calculate the following probabilities. Express your answer as a fraction in lowest terms. a) The numbe

saul85 [17]

A).1/2(4,5,6)

B).1/2(1,2,3)

C).1/6(6)

Can I get brainliest please?

4 0

2 years ago

PLSS HELP THE TEACHER IS ASKING FOR MY ANSWERS CUZ I WAS SUPPOSED TO DO IT AND I NEVER WAS PREPARED PLSSS HELP IM NEXT

Goshia [24]

Okay!!! What are the questions?

8 0

1 year ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

2 years ago