The mass of chlorine that react with 9.00 g of Al to form AlCl3 is 35.465 grams
Explanation
write the equation for reaction
that is
2 Al + 3 Cl2 = 2 Al CL3
find the moles of Al reacted
moles = mass/molar mass
9 g/ 27 g/mol = 0.333 moles of Al
by use of mole ratio between Al to Cl2 which is 2:3 find the moles of Cl2
mole of cl2 = 0.333 x3/2 = 0.4995 moles
mass of Cl2 is therefore = moles x molar mass
= 0.4995 x71 = 35.465 moles
Answer:
R is universal gas constant
It is has fixed value which would depend upon the units in which P,V and T expressed in the equation PV=nRT
R=
nT
PV
Answer:
C. the relative molecular mass of the compound
Explanation:
Like molecular formulas, empirical formulas are not unique and can describe a number of different chemical structures or isomers. <u>To determine an empirical formula, the relative molecular mass of the composition of its elements</u> can be used to mathematically determine their ratio.
Homogeneous mixture. (all of the different components of the salad are shown)
