9^5 is 9*9*9*9*9 you * 9 by how ever many little number there is so you get 59049
and with 9^3 its 9*9*9 729
its NEVER 9*3 or 9*5 you have to times the same number () time the littler number it telling you how many time to do so
So here you're using system of equations. You can solve systems by graphing, elimination, or substitution. Ill use substitution. First lets solve for x. take the second equation and add y to both sides to get x by itself:
x - y = 75
x = y + 75 now plug y+75 in for x in the first equation
x + y = 743
(y +75) +y = 743 solve for y
2y +75 = 743 subtract 75
2y = 668 divide both sides by 2
y = 334
now plug this into any of the 2 equations to solve for x i chose the second one
x - y = 75
x - 334 = 75 add 334 to both sides
x = 409
This means x, sold before the tournament is 409 and y, sold at the door is 334. That means the assistant is wrong and accidentally flipped the two answers
Answer:
Step-by-step explanation:
Let x represent the length of the rectangle. The the width is (4x+2) and the area is ...
x(4x+2) = 342
2x² +x - 171 = 0 . . . . . divide by 2, rearrange to standard form
(2x +19)(x -9) = 0 . . . factor
x = -19/2 or +9 . . . . . the length is the positive solution: 9
(4x+2) = 4(9) +2 = 38 . . . . find the width from the length
The length of the rectangle is 9 meters. The width is 38 meters.
Not sure what exactly you meant, so i solved for both possibilities...
Answer: a=-2
assuming you mean a+2/2=-1.....
a+2/2=-1
simplify..
a+1=-1
subtract 1 from both sides
a=-2
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Answer: a=-4
assuming you mean (a+2)/2=-1...
(a+2)/2=-1
simplify...
a/2+2/2=-1
simplify
a/2+1=-1
subtract 1 from both sides
a/2=-2
multiply both sides by 2
a=-4