Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
Answer:
144,148,152
Step-by-step explanation:
Here we will have, 4x + 4(x+1) + 4(x+2) = 444
=> x + (x+1) + (x+2) = 111 (dividing both sides by 4)
=>x + x+1 + x+2 =111
=> 3x + 3 = 111
=> 3x = 108
=> x = 36.
So, the three desired numbers 4x, 4(x+1) and 4(x+2) are,
4*36, 4*(36+1) and 4*(36+2)
That means the numbers are, 144, 148 and 152.
Answer: the equation is slope-intercept form y = -2/3x
1) 65+57= 122
180-122= 58
2) 40+90=130
180-130=50
3) 130+20=150
180-150=30
4) 85+50= 135
180-135=45
Sorry, IDK the rest. So so sorry.
