Answer: 81
To get this answer, you do two things
1) Take half of the x coefficient 18 to get 9
2) Square the result from the previous step to get 9^2 = 9*9 = 81
This value is added on to get x^2+18x+81 which factors to (x+9)^2 confirming we have a perfect square trinomial
Answer:
the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Step-by-step explanation:
From the given question.
Let p be the length of the of the printed material
Let q be the width of the of the printed material
Therefore pq = 2400 cm ²
q =
To find the dimensions of the poster; we have:
the length of the poster to be p+30 and the width to be
The area of the printed material can now be:
=
Let differentiate with respect to p; we have
Also;
For the smallest area
p² = 3600
p =√3600
p = 60
Since p = 60 ; replace p = 60 in the expression q = to solve for q;
q =
q =
q = 40
Thus; the printed material has the length of 60 cm and the width of 40cm
the length of the poster = p+30 = 60 +30 = 90 cm
the width of the poster = = = 40 + 20 = 60
Hence; the dimension of the poster = 90 cm length and 60 cm width i.e 90 cm by 60 cm.
Answer:
48/b
Step-by-step explanation:
32÷16=2 so it takes two minutes per airplane. if she makes airplanes for 96 minutes at the same pace (2 min per airplane) then you need to divide 96 by 2 which gives you 48!
Answer:
<h2>
(-3,8)</h2><h2>
Or</h2><h2>
x=-3 and y=8</h2>
Step-by-step explanation:
<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>
Note that the domain of h is <span>[0,∞]</span>.
By differentiating,
<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>
by factoring out <span>34</span>,
<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>
by finding the common denominator,
<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>
<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>
Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.
Hence, the critical numbers are <span>t=0,1</span>.
I hope that this was helpful.