What problem there is no problem explain to me the problem
A=2(wh+lw+lh)
l=8m
w=3m
h=2m
A=2((3m)(2m)+(8m)(3m)+(8m)(2m))
A=2((6m)+(24m)+(16m))
A=2(46m)
A=92m
Area is 92m
Answer:
Step-by-step explanation:
a) the points (0,60) and (6.0) are the intercept points for the graph of the car slowing down ( accelerating in the opposite direction than it's traveling)
we already know the slope of the line b/c that the rate at which it's slowing .. -10 =m which is the slope of the line .. down 10
use the point-slope formula y-y1 = m(x-x1) and plug in either given point for (x1,y1)
b) y -60 = -10(x-0)
y= -10x+60
thats the slope-intercept form of the equation
For this case we must express the following expression algebraically:
<em>"The quotient of b and 2 minus 4 is at least 26"</em>
So we have to:
The quotient of b and 2 minus 4, is represented as:
We have different signs subtracted and the sign of the major is placed:
Thus, the expression is written as:
ANswer:
A - 1.2b = - 3 ⇒ eq. 1
0.2b + 0.6a = 12 ⇒ eq. 2
a - 1.2b = - 3
a = 1.2b - 3 ⇒ eq. 3
Substitute eq. 3 to eq. 2
0.2b + 0.6(1.2b - 3) = 12
0.2b + .72b - 1.8 = 12
Combine like terms
0.92b = 12 + 1.8
0.92b = 13.8 ⇒ divide both sides by 0.92 to get the value of b
<span>b = 15
</span>Substitute the value of b to eq. 3
a = 1.2b - 3
a = 1.2(15) - 3
<span>a = 15
</span>to check: substitute the values of a and b to:
eq. 1
a - 1.2b = - 3
15 - (1.2)(15) = -3
15 - 18 = - 3
- 3 = -3 ⇒ correct!
eq. 2
0.2b + 0.6a = 12
(0.2)(15) + (0.6)(15) = 12
3 + 9 = 12
12 = 12 ⇒ correct!