Answer:
ΔSTU ≅ ΔBDC
Step-by-step explanation:
In ΔSTU and ΔBDC,
∠S ≅ ∠B [Given]
∠T ≅ ∠D [Given]
SU ≅ BC [Given]
Since, two corresponding angles and non included side of the angles are equal in measure.
Therefore, ΔSTU ≅ ΔBDC [By AAS property of congruence]
Answer:
3
Step-by-step explanation:
Answer:
23.52 miles
Step-by-step explanation:
Let us find the number of miles that they would have run.
Kana starts at 9:35 a.m. and runs at an average rate of 7 mph.
Let the time she has spent so far be t.
Speed is given as:
s = d / t
where d = distance and t = time
=> d = s * t
Therefore, for Kana:
d = 7 * t = 7t _____________(1)
Ji-Hun starts at 10:00 am (25 minutes after Hannah) and runs at an average rate of 8 mph.
25 minutes = 25/60 hour = 0.42 hour
So, his time (compared to Kana's) is t - 0.42.
therefore, for Ji-Hun:
d = 8 * (t - 0.42)
=> d = 8t - 3.36 ____________(2)
Equating (1) and (2):
7t = 8t - 3.36
=> 8t - 7t = 3.36
t = 3.36 hours
Therefore, let us find d:
d = 7 * 3.36 = 23.52 miles
So, Ji-Hun will catch up to Kana after 23.52 miles.
Why not? Because every math system you've ever worked with has obeyed these properties! You have never dealt with a system where a×b did not in fact equal b×a, for instance, or where (a×b)×c did not equal a×(b×c). Which is why the properties probably seem somewhat pointless to you. Don't worry about their "relevance" for now; just make sure you can keep the properties straight so you can pass the next test. The lesson below explains how I kept track of the properties.
