If b is in the first position then c can be in any 1 of the remaining 6 positions.
If we start with ab then the letter c can be in any one of 5 positions and if we have aab there are 4 possible positions for c and so on.
So the total number of possible sequences where b comes first = 6+5+4+3+2+1 = 21.
The same argument applies when c comes before b so that gives us 21 ways also.
So the answer is 2 *21 = 42 different sequences.
A more direct way of doing this is to use factorials:-
answer = 7! / 5! = 7 * 6 = 42.
( We divide by 5! because of the 5 a's.)
6x + 9 < 63
Subtract 9 from both sides.
6x < 54
Divide 6 by both sides.
x < 9
Answer:
40.56
Step-by-step explanation:
you need the circumference of the cirle aka perimeter of circle so 8(pi) and then because its only half, divided by 2... 12.56
now you hgave circumference so add 12.56 to 28 and there you go. you can round how ever necessary
Answer:
8
Step-by-step explanation:
8 is the correct answer
