Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
G = 4n is the correct equation to use. Eg 10 x 4 = 40, 18 x 4 = 72 and 21 x 4 = 84
The diagonal of a rhombus divides it into two congruent isosceles triangles.
So ∠CBD ≅ ∠CDB
∠CBD + ∠CDB + 68 = 180
2∠CBD = 180 - 68 = 112
∠CBD = 56
We also have
∠BDE + ∠E + ∠DBE = 180
∠DBE = 180 - 73 - 36 = 71
∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15
Answer: ∠EBC = 15 degrees
Answer:
There are 6 equilateral triangles
you get an isosceles triangle
the height of the equilateral triangle is 4
this is all I have so far :)
% change = (new value - old value)/old valu x 100 = (1,045 - 950)/950 x 100 = 95/950 x 100 = 0.1 x 100 = 10%
