Answer:
the idea behind the recurring decimal as a fraction, is to first off, multiply or divide by some power of 10, in order that we leave the recurring decimal to the right of the decimal point.
then we multiply by a power of 10, in order to move the repeating digits to the left of the decimal point, anyhow, let's proceed.
notice, we first divided by 10, to move the decimal point over to the right by 1 slot, then we multiplied by 100, to move it two digits over the decimal point, namely the repeating "12", thus we use 100. i think
Step-by-step explanation:
![x^{\frac{1}{2}} = \sqrt[2]{x}](https://tex.z-dn.net/?f=%20x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Csqrt%5B2%5D%7Bx%7D%20)
and ![3^{-\frac{1}{2}} = \frac{1}{3^{\frac{1}{2}} } = \frac{1}{\sqrt[2]{3}}](https://tex.z-dn.net/?f=%203%5E%7B-%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B3%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%7D%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B2%5D%7B3%7D%7D%20)
so
and you rationalize denominator by multiplying numerator and denominatr by 
so that gives--
Your answer is 
To solve this, you need to do 1,266-451. that equals 815. then, divide 815 by 19. you should get 43. hope that helps.
Answer:
y = x - 2 could not be the function equation.
Step-by-step explanation:
The function with an input of 3 has an output of 5.
So, y = 2x - 1 can be the function as y(3) = 2 × 3 - 1 = 6 - 1 = 5.
Now, y = x + 2 can also be the function as y(3) = 3 + 2 = 5
Again, y = 3x - 4 can also be the function as y(3) = 3 × 3 - 4 = 9 - 4 = 5
But y = x - 2 can not be the function as y(3) = 3 - 2 = 1 ≠ 5
Therefore, y = x - 2 could not be the function equation. (Answer)
Answer:
$20
Step-by-step explanation:
She has 5 dollars originally, she sells 2 pillows for $10 each that = $20 and then she sold one for $5 but she spent a original $5 on material so $25 - $5 = $20
