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1 year ago

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1 Ben's Barbershop has a rectangular logo for their business that measures 7 feet long with an area that is exactly the maximum

area allowed by the building owner. Create an equation that could be used to determine M, the unknown side length of the logo..

1 answer:

fiasKO [112]1 year ago

6 0

The equation that could be used to determine the unknown side length, M of the logo is A = 7M

<h3>How to determine the equation?</h3>

From the question, we have the following parameters:

Logo: Rectangle
Length, L = 7 feet

Represent the area of the logo with A, and M represents the unknown side

The area (A) of the rectangle is calculated using:

A = L * W

Substitute 7 for L, and M for W

A = 7M

Hence, the equation that could be used to determine the unknown side length, M of the logo is A = 7M

Read more about areas at:

brainly.com/question/24487155

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Complete Question

Answer:

a

$SE = 0.66}$

b

$-3.29 < \mu_1 - \mu_2 < -0.70$

Step-by-step explanation:

From the question we are told that

The sample size is n = 60

The first sample mean is $\= x _1 = 8$

The second sample mean is $\= x _2 = 10$

The first variance is $v_1 = 0.25$

The first variance is $v_2 = 0.55$

Given that the confidence level is 95% then the level of significance is 5% = 0.05

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

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Generally the first standard deviation is

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=> $\sigma_1 = 0.5$

Generally the second standard deviation is

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=> $\sigma_2 = \sqrt{0.55}$

=> $\sigma_2 = 0.742$

Generally the first standard error is

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$SE_1 = \frac{0.5}{\sqrt{60} }$

$SE_1 = 0.06$

Generally the second standard error is

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$SE_2 = \frac{0.742}{\sqrt{60} }$

$SE_2 = 0.09$

Generally the standard error of the difference between their mean scores is mathematically represented as

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=> $SE = \sqrt{0.06^2 +0.09^2 }$

=> $SE = 0.66}$

Generally 95% confidence interval is mathematically represented as

$(\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } * SE) < \mu_1 - \mu_2 < (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } * SE)$

=> $(8 -10) -(1.96 * 0.66) < \mu_1 - \mu_2 < (8-10) +(Z_{\frac{\alpha }{2} } * 0.66)$

=> $-3.29 < \mu_1 - \mu_2 < -0.70$

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