F(x) can also mean y
Use data point 2 to begin with as it makes things easier because it contains a 0 x=0 y=3
A. f(x)= -3x+2
f(0)=-3(0)+2
f(0)= 0+2
y=2which doesn’t correspond with the y= 3above
B.f(x)=-2x+3
f(0)=0+3
Y=3 which does correspond with the y=3 above
C.f(x)=2x-3
f(0)=2(0)-3
y=-3 which doesn’t correspond with the y= 3above
D.f(x)=3x-2
f(0)=3(0)-2
y=-2 which doesn’t correspond with the y= 3above
So function B. f(x)=-2x+3 is the only answer
Answer: In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
Equation 2 is the only linear one due to the fact that there is no exponent on the x or y values.
Answer:
first blank- 2 second blank- 3 1/2 or 4 may be 3 too
Step-by-step explanation:
well when you look at the shape you can go from a to b and count the blocks which it would be 2
and you would want to do the same thing with C,D
Taking
and differentiating both sides with respect to
yields
![\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B3x%5E2%2By%5E2%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B7%5Cbigg%5D%5Cimplies%206x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D0)
Solving for the first derivative, we have
Differentiating again gives
![\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B6x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B0%5Cbigg%5D%5Cimplies%206%2B2%5Cleft%28%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cright%29%5E2%2B2y%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D0)
Solving for the second derivative, we have
Now, when
and
, we have
