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bearhunter [10]

1 year ago

10

What is the resulting equation when the expression for y in the second equation is substituted into the first equation? 3x y = 1

y = 6 - 4x 7x 6 = 1 -x 6 = 1 x 6 = 1.

1 answer:

Natali5045456 [20]1 year ago

8 0

After putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

GIven:

The equations are:

$3x + y = 1\\
y = 6 - 4x$

It is required to put the value of y from second equation to the first equation.

<h3>How to solve equations?</h3>

The value of y from the second equation is,

$
y = 6 - 4x$

Now, put this value of y in the first equation as,

$3x + y = 1\\
3x+(6 - 4x)=1\\
3x+6-4x=1\\
-x=-5\\
x=5$

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

For more details about equations, refer to the link:

brainly.com/question/2263981

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meriva

Answer:

$\tan \theta = - \frac{1}{5} = - 0.2$

$\cos \theta = 0.98$

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Step-by-step explanation:

It is given that $\cot \theta = - 5$ and $\theta$ is in the fourth quadrant.

So, only $\cos \theta$ will have positive value and $\sin \theta$ , $\tan \theta$ will have negative value.

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We know, that $\sec^{2} \theta - \tan^{2} \theta = 1$

⇒ $\sec \theta = \sqrt{1 + \tan^{2} \theta } = \sqrt{1 + (- \frac{1}{5} )^{2} } = 1.019$

{Since, $\cos \theta$ is positive then $\sec \theta$ will also be positive}

⇒ $\cos \theta = \frac{1}{\sec \theta} = \frac{1}{1.0198} = 0.98$ (Answer)

We know, that $\csc^{2} \theta - \cot^{2} \theta = 1$

⇒ $\csc \theta = - \sqrt{1 + \cot^{2} \theta } = - \sqrt{1 + (- 5 )^{2} } = - 5.099$

{Since, $\sin \theta$ is negative then $\csc \theta$ will also be negative}

⇒ $\sin \theta = \frac{1}{\csc \theta} = \frac{1}{- 5.099} = - 0.196$ (Answer)

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