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1 year ago

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I WILL GIVE BRAINLIEST TO WHO ANSWERS RIGHT!!! The measure of A is 100°. Angles A and B are supplementary. What is mB? A.mB = 10

° B.mB = 80° C.mB = 90°
D.mB = 180°

1 answer:

vova2212 [387]1 year ago

4 0

Answer:

B. m∠B = 80°

Step-by-step explanation:

Supplementary angles are two angles that sum to 180°

⇒ m∠A + m∠B = 180°

⇒ 100° + m∠B = 180°

⇒ m∠B = 180° - 100°

⇒ m∠B = 80°

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Answer:

The answer to your question is: y = -2/3 x + 18

Step-by-step explanation:

Data

Point = (-9, 12)

line y = 3/2x -1/2 perpendicular

Process

The line must be perpendicular to the line given. Then,

slope is the line given = 3/2, we change it because the lines must be perpendicular ,

New slope M = -2/3

New line y-y1 = m(x - x1)

y - 12 = -2/3 (x + 9) Substitution

3( y - 12) = -2(x + 9)

3y - 36 = -2x - 18 Simplify

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2 years ago

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( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
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midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
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point x=(15,8)

y is midpoint of A and D
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B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
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X=15,8
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x1=15
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we need to find AD and BC and XY
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A=5,8
D=21,0
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D= $\sqrt{256+64}$
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so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

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XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
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X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
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2 years ago

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