To calculate the strength of the eye lens, we use the formula
( thin lens formula)
Here, u is the object distance and v is image distance.
Given, and
Therefore,
Thus, strength of the eye lens is
Newton's second law states that (Force is mass times acceleration). Out of the given options, “a 10 kg ball thrown with a 50 Newton force”, an example have the greatest acceleration.
<u>Explanation:
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To do the calculation, we already have the formula given derived from Newton’s second law of motion. To know the acceleration, we can simply modify the formula as,
For the 10kg ball threw in 50N, we have mass = 10 kg and Force = 50 N
Acceleration =
Similarly for 1 kg ball threw in 0.5N, substituting the values, we get
,
Acceleration =
For launching 50kg student by catapult of 100N,
acceleration =
For accelerating 500 kg car in 1000N engine,
acceleration =
Answer:
C 3.33 Ω
Explanation:
From the equation given 1 / Rtot = 1/10 + 1/5 = 3/10
then Rtot = 10/3 = 3.33 Ω
As an aside:
When there are only two resistors in parallel, the equivalent R is
= R1*R2 / (R1 + R2) = 10*5 / (10+5) = 50 / 15 = 3.33 Ω
Answer:
The Frequency of the wave is 0.2Hertz
The period is 2seconds
Explanation:
We are asked to find the frequency and period
Frequency is the number of oscillations completed in one seconds
If five waves were made from the same source in 10 seconds, hence;
Frequency = number of oscillation/Time
Frequency = 5/10
Frequency = 0.5Hertz
Next is to get the period
Period = 1/Frequency
Period = 1/0.5
Period = 2seconds
The horizontal component of the velocity of the ball is calculated by multiplying the speed by the cosine of the given angle.
x-component of speed = (31 m/s)(cos 35°)
= 25.39 m/s
Thus, the horizontal velocity component of the ball is 25.39 m/s.