4x^2-25= (2x)^2-5^2=(2x-5)(2x+5)
Used: a^2-b^2=(a+b)(a-b)
Answer:
third option: log_2 1/3
Step-by-step explanation:
change of base formula:
log_b a= (log_x a)/(log_x b)
(log 1/3)/(log 2)
apply reverse change of base formula
2 from log 2 becomes new base, and 1/3 becomes the other number
=log_2 1/3
Answer:
yes
Step-by-step explanation:
Answer:
Each of the 7 friends could be present or not present (2 cases) at the party giving total of 27 scenarios.
Since at least one must be present we exclude the case that none of them is present. So the answer would be:
27−1=127.
Step-by-step explanation:
i actually dont know but can you report me and dont ask
Factorise x^2+6x+8=0 to get (x+4)(x+2)=0
Solve to get x=-4, x=-2
Factorise x^2+6x+13=0 (I assumed you mistyped and wrote * instead of +)
Use the quadratic formula and you find that there are no real roots so the answer for this is just x=-4, x=-2
Tell me if I made any mistakes
