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1 year ago

What is the slope of the line that asses through these two points? (1, -2) (3, 4)

Mathematics

2 answers:

Anton [14]1 year ago

5 0

Answer:

Step-by-step explanation:

slope = y2-y1/x2-x1

from the question above,

X1= 1 Y1= -2

X2= 3 Y2= 4

SLOPE OF THE LINE

= 4--2/3-1

= 4+2/2

= 6/2= 3

slope of the line = 3

dusya [7]1 year ago

3 0

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{4}-\stackrel{y1}{(-2)}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}}\implies \cfrac{4+2}{2}\implies \cfrac{6}{2}\implies 3$

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What two sums are equal to 3 3/4? Pls show work.

Rina8888 [55]

3 + 3/4 = 3 3/4

Ans: 3 and 3/4

2 + 1 3/4 = 3 3/4

Ans: 2 and 1 3/4

5 0

2 years ago

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

dexar [7]

Answer:

idk

Step-by-step explanation:

7 0

2 years ago

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Ten times an integer is added to seven times it’s square. If the result is 152, what was the original number?

Bess [88]

Answer:

Required number is 4.

Step-by-step explanation:

Let the required number be a.

Given,

Sum of ten times the integer and seven times it’s square is 152.

= > Ten times of a + seven times of it's square = 152

= > 10( a ) + 7( a )^2 = 152

= > 10a + 7a^2 - 152 = 0

= > 7a^2 + 10a - 152 = 0

= > 7a^2 + ( 38 - 28 )a - 152 = 0

= > 7a^2 + 38a - 28a - 152 = 0

= > a( 7a + 38 ) - 4( 7a + 38 ) = 0

= > ( a - 4 )( 7a + 38 ) = 0

= > a = 4 or - 38 / 7

Hence the required number is 4.

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2 years ago

According to the synthetic division below, which of the following statements are true? Check all that apply. -5(2 6 -8) -10 20 _

Sunny_sXe [5.5K]

***(2x²+6x-8):(x+5)=2x-4
     -2x²-10x
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
   -4x-8
          4x+20
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
              12 ⇒ A. statement is true.

***When x=-5⇒2*(-5)²+6*(-5)-8=12⇒B. statement is true.

***2x²+6x-8 can also be written as (x+5)*(2x-4)+12 so (x+5) is a factor of 2x²+6x-8⇒C. statement is true.

***When x=5⇒2*5²+6*5-8=72 is not 12⇒D. statement is not true

***(2x²+6x-8):(x+5)=2x+16
     -2x²+10x
    ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
        16x-8
             -16x+80
      ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
                     72⇒F. statement is not true

***E. statement is not true.

8 0

2 years ago

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Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g

SpyIntel [72]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see $\bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad B
\end{array}$

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.

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2 years ago

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