The logic is there are six sides to each die, so for each number on one die you can pair with six different numbers on the other die. Therefore, the probability of rolling a prime number on two dice is 15/36, which reduces to 5/12.
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(24y^5)/(15x^8) * 4x^4/(8y²)
<span>Reduce the common factors for the numerator and denominator and multiply the fractions altogether to get... </span>
<span>24/8 * y^(5 - 2) * 4/15 * 1/x^(8 - 4) </span>
<span>= 3y³ * 4/15 * 1/x^4 </span>
<span>= 4y³/(5x^4) </span>
<span>I hope this helps!</span>
First we find the mean (average)
(7 + 8 + 9 + 9 + 10 + 11)/6 = 54/6 = 9
now we subtract the mean from every data number....and square it
7 - 9 = -2...-2^2 = 4
8 - 9 = -1...-1^2 = 1
9 - 9 = 0....0^2 = 0
9 - 9 = 0...0^2 = 0
10 - 9 = 1....1^2 = 1
11 - 9 = 2....2^2 = 4
now we find the mean (average) for those numbers
(4 + 1 + 0 + 0 + 1 + 4) / 6 = 10/6 = 1.67...this is the variance
to find the standard deviation, take the sqrt of the variance
sqrt 1.67 = 1.29 <== ur answer