0.25 is 1/4 if that's what youre asking, i'm not sure,
Answer:
20165
Step-by-step explanation:
Given:
Length/height (h) of cylindrical test tube = 152 mm
Radius of cylindrical test tube = 6.5 mm
Volume =
Required:
Volume of cylinder to nearest whole number
Solution:
The volume is given as
Take π as 3.14 and plug the values of r and h into the volume formula.
Volume of the test tube = 20165 mm³ (nearest whole number)
These 2 equations has no solution and the equations are independent of each other.
<u>Step-by-step explanation:</u>
-10x² -10y² = -300 ----a
5x² + 5y² = 150 ---- b
While trying to solve this,
We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.
10x² + 10y² = 300 ----c
-10x² -10y² = -300 ---a
Everything cutoff, we will get 0, and there is no solution to these equations.
Answer:
75
Step-by-step explanation:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
<em>A = 84 mg</em>