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Answer:
a. 1.48 seconds
Step-by-step explanation:
You want to find the larger value of t such that h(t) = 10.
-16t^2 +25t +8 = 10
16t^2 -25t +2 = 0 . . . . subtract the left side to get standard form
Using the quadratic formula, we find the values of t to be ...
t = (-(-25) ± √((-25)^2 -4(16)(2)))/(2(16)) = (25±√497)/32
t ≈ 0.08 or 1.48
The ball goes in the hoop about 1.48 seconds after it is thrown.
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<em>Additional comment</em>
The quadratic formula tells us the solution to ...
ax² +bx +c = 0
is given by ...
Here, we have a=16, b=-25, c=2. Of course, our variable is t, not x, but the relation is the same.
Answer:
Step-by-step explanation:
Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
r = linear correlation coeff = 0.952
H_0: r =0\\
H_1 :r\neq 0
(Two tailed test)
r difference = 0.952
n=8
Std error = \sqrt{\frac{1-r^2}{n-2} } =0.12496
Test statistic t = 0.952/0.12496 = 7.618
Alpha = 0.05
df = 6
p value = 0.000267
This implies H0 is rejected.
There exists a linear relation between the variables and r cannot be 0
0.952^2 = 0.906=90.6% of variation in weight can be explained by the linear relationship between weight and chest size
Sydney would arrive one hour before Nathan. 24/12=2 and 24/8=3
Multiply 5/8 by 64
=40
1:4 means a fourth of them
so basically 10 out of 40
now just subtract 10 from 40 to get the amount of classical players
10 jazz & 30 classical
