Soooooo sorry but I only understood part a and c.
sorry
In a trapazoid the diagonals are the same so therefore the two equations equal echother
3x+7=5x-11 solve for x by combining like terms
18=2x then divide to unto multiplication
9=x
9 is the value of x
I hope I've helped!
1 3/4 of the cup will be the other liquid because if you take 1/4 from 2, that would be 1 3/4.
Answer: See the diagram below
=================================================
Explanation:
The base is always perpendicular to the height, meaning the two form a 90 degree angle (aka right angle).
In column 1, refer to the figures as 1, 2 and 3 (working top to bottom).
In column 2, refer to the figures as A, B, C
Figure 1 matches with figure B
Figure 2 matches with figure C
Figure 3 matches with figure A.
These matches are of course the base with the proper height.
For the first one we divide every element by sqrt3
we get
q+2/sqrt3 =sqrt5/sqrt3
q=(sqrt5-2)/sqrt3
q=sqrt3*sqrt5-2*sqrt3/3
q=sqrt15-2sqrt3/3
which is the third option
For the second one
sqrt(2y-5) +4=8
first we move the 4 to the right
sqrt(2y-5)=4
we remove the square root by bringing to the power of two
2y-5=16
2y=21
y=21/2
y=10 1/2
third option