Answer:
Total mass of leaked fluorine in six months= 0.405 kg
Explanation:
From the given,
Leaked mass of freon = 35.12 gm
Molecular mass of freon =
Total weeks per month = 4
Fluorine released into the air in total weeks =
3 molecules of fluorine is present in the freon
Total mass of fluorine leaked in six months =
Equation :
PbF2 ------> Pb2+ + 2F-
Solubility product is given as:
Ksp = [Pb2+][F-]^2
let x = [Pb2+]
Ksp = x(2x)^2 = 4(x)^3 = 4(2.08*10^-3)^3
Ksp = 3.60*10^-8
Not sure how they're connected to atmosphere other than polluting it with hot ash, but im fairly certain it creates land masses which separate oceans and form land underwater with certain underwater volcanoes
Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
Answer:
it is the one below that. NO, because it debt net the octet rule