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Angelina_Jolie [31]

1 year ago

14

Give a brief description of the symptoms associated with dissociative fugue.

1 answer:

fomenos1 year ago

3 0

Answer:

People may seem and act normally during the fugue, or they may appear moderately bewildered and draw no notice. When the fugue is over, however, people are thrown into a new scenario with no recall of how they got there or what they were doing.

Explanation:

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Is there a difference between a homogeneous mixture of hydrogen and oxygen in a 2:1 ratio and a sample of water vapor?

Feliz [49]

Answer:

Yes

Explanation:

There is a difference between the homogeneous mixture of the hydrogen and the oxygen in a 2:1 ratio and the sample of the water vapor.

In the homogeneous mixture of the hydrogen and the oxygen which are present in the ratio, 2:1 , the elements are not chemically combined. They are explosive also as both shows their specific properties. They can be separated by physical means (Condensation, diffusion).

On the other hand, in water vapor, the two elements are chemically bonded in a specific mixture which cannot be separated via physical means. Water has its unique properties and they can be separated by chemical means only.

5 0

2 years ago

If a gas had a volume of 6.7 L and started at STP, what would the new pressure be

Phantasy [73]

The new pressure would be = 4.46 atm

<h3>Further explanation</h3>

Given

V₁=6.7 L(at STP, 1 atm 273 K)

V₂=1.5 L

Required

The new pressure

Solution

Boyle's Law

At a constant temperature, the gas volume is inversely proportional to the pressure applied

$\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}$

P₂ = (P₁V₁)/V₂

P₂ = (1 atm x 6.7 L)/1.5 L

P₂ = 4.46 atm

5 0

1 year ago

Moseley made revisions to the periodic table that resolved some of the problems with Mendeleev’s version. Which of these was a r

olga55 [171]

The result of Moseley's revisions were that the elements were arranged in atomic number order rather than atomic mass order.

5 0

2 years ago

in the laboratory a student dilute 13.3 ml of a 10.8 m hcl solution to a total of 300.0 ml what is the concentration of the dilu

krek1111 [17]

<u>Answer:</u> The concentration of the diluted solution is 0.4788M

<u>Explanation:</u>

To calculate the concentration of the diluted solution, we use the following equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of HCl solution

$M_2\text{ and }V_2$ are the molarity and volume of the diluted HCl solution.

We are given:

$M_1=10.8M\\V_1=13.3mL\\M_2=?M\\V_2=300mL$

Putting values in above equation, we get:

$10.8\times 13.3=M_2\times 300\\\\M_1=0.4788M$

Hence, the concentration of the diluted solution is 0.4788M

6 0

2 years ago

5. What is the final "Celsius" temperature if 2.40 L of gas at 30.5 C is cooled until the volume reaches 1.00 L at constant pres

slega [8]

Answer:

Final temperature of the gas = -146.63 °C

Explanation:

At constant pressure, volume and temperature of the gases are related as:

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Where,

V1 = Initial volume = 1.00 L

V2 = Final volume = 2.40 L

T1 = Initial temperature = 30.5 °C = 30.5 + 273.15 = 303.65 K

Now, substitute the values in the above equation,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{2.40\;L}{303.65}=\frac{1.00\;L}{T_2}$

$T_2=\frac{1.00\times 303.65}{2.40}$

T2 = 126.52 K

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

T( °C) = T(K) - 273.15

= 126.52 - 273.15 = -146.63 °C

7 0

2 years ago