Function 1:
f(x) = -x² + 8(x-15)f(x) = -x² <span>+ 8x - 120
Function 2:
</span>f(x) = -x² + 4x+1
Taking derivative will find the highest point of the parabola, since the slope of the parabola at its maximum is 0, and the derivative will allow us to find that.
Function 1 derivative: -2x + 8 ⇒ -2x + 8 = 0 ⇒ - 2x = -8 ⇒ x = -8/-2 = 4
Function 2 derivative: -2x+4 ⇒ -2x + 4 = 0 ⇒ -2x = -4 ⇒ x = -4/-2 ⇒ x= 2
Function 1: f(x) = -x² <span>+ 8x - 120 ; x = 4
f(4) = -4</span>² + 8(4) - 120 = 16 + 32 - 120 = -72
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Function 2: </span>f(x) = -x²<span> + 4x+1 ; x = 2
</span>f(2) = -2² + 4(2) + 1 = 4 + 8 + 1 = 13
Function 2 has the larger maximum.
Answer:
Step-by-step explanation:
In Δ AFB,
∠AFB + ∠ABF + ∠A = 180 {Angle sum property of triangle}
90 + 48 + ∠1 = 180
138 + ∠1 = 180
∠1 = 180 - 138
∠1 = 42°
FC // ED and FD is transversal
So, ∠CFD ≅∠EDF {Alternate interior angles are congruent}
∠2 = 39°
In ΔFCD,
∠2 + ∠3 + ∠FCD = 180
39 + ∠3 + 90 = 180
129 +∠3 = 180
∠3 = 180- 129
∠3 = 51°
4/10 would be left you would make it a whole fraction at 10/10 then minus 4/10 and minus 2/10 that leaves 4/10 of cards. Hope this helps you out.
The volume of a room = length * width * height
=12z³-27z
And by the analysis:
The volume = 12z³-27z
= ( 3z ) ( 4z²-9 ) ⇒ by taking (3z) common
= ( 3z )( 2z+3 )( 2z-3 ) ⇒ <span>the difference between two squares
So </span><span>the dimensions of the room will be 3z , 2z+3 , 2z-3
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I have attached tha problem
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I'm sorry if this is wrong
<em>I</em><em> </em><em>tried</em><em> </em>
Let present age of Anne be x
Two years ago she was Jim's age which is 10 yrs she is now double that age
10(x-2)
10x-20
= She is now 20 yrs