Answer:
A) m = 0.062
B) 202.87 thousand dollars
C) Original price = 116.07 thousand dollars. $6000 is called the error term.
Step-by-step explanation:
We are given the following in the question:
Price = 47.87+0.062(size)
The above equation is regression equation where price is in thousand dollars and size in square feet.
Let p be the prize and s be the size.
Comparing it to linear equation, we have,
where m is the slope and c is the y-intercept.
m = 0.062
c = 47.87
A) slope of the line
The slope of line tells the rate of change. Thus, it tells the change in price if the size of house is increased by 1 square feet.
The price of house increases by 0.062 thousand dollars if the size of house is increased by 1 square feet.
B) Price of house
We are given s = 2500. Putting this value in the equation.
Thus, the price of a 2500 square feet house is 202.87 thousand dollars.
C) We are given s = 1100
Putting the value in the equation:
Original price = 116.07 thousand dollars
Asking price =
The buyer is asking for 110.07 thousand dollars.
$6000 is called the error term.
Answer:
(4x + 7y)(4x - 7y)
Step-by-step explanation:
Rewrite 16 as 4^2
= 4^2x^2 - 49y^2
Rewrite 49 as 7^2
= 4^2x^2 - 7^2y^2
Apply the Exponent Rule Pt 1 ((a^m*b^m =(ab)^m))
= (4x)^2 - 7^2y^2
Apply the Exponent Rule Pt 2
= (4x)^2 - (7y)^2
Apply Difference of Squares Formula (( x^2-y^2 = (x + y)(x - y)
= (4x + 7y) (4x - 7y)
d(x) = { (x,y): y = sqrt(x) and y >=0 }
since sqrt function requires x to be >=0 so
<u>x >= 0</u>
IQR = 40
1) Put the numbers in order: 40, 45, 50, 60, 60, 75, 90, 90, 120
2) Find the median: Median is 60 (the 2nd one)
3) Place parentheses around the numbers above and below the median. For easy identification of Q1 and Q3. (40, 45, 50, 60,) 60, (75, 90, 90, 120)
4) Find the Q1 and Q3. Q1 = median of the lower half of the data; Q3 = median of the higher half of the data. Q1 and Q3 have even sets so its median cannot be defined.
5) Had both sets contain odd sets, the median of Q1 is subtracted from the median of Q3 to get the IQR.
We can then use the Alternative definition of IQR.
IQR is the difference between the largest and smallest values in the middle 50% of a set data.
40, 45, 50, 60, 60, 75, 90, 90, 120
Middle 50% is 50, 60, 60, 75, 90; IQR = Largest value - smallest value;
IQR = 90 - 50 = 40
