Hi there!
We can calculate dy/dx using implicit differentiation:
xy + y² = 6
Differentiate both sides. Remember to use the Product Rule for the "xy" term:
(1)y + x(dy/dx) + 2y(dy/dx) = 0
Move y to the opposite side:
x(dy/dx) + 2y(dy/dx) = -y
Factor out dy/dx:
dy/dx(x + 2y) = -y
Divide both sides by x + 2y:
dy/dx = -y/x + 2y
We need both x and y to find dy/dx, so plug in the given value of x into the original equation:
-1(y) + y² = 6
-y + y² = 6
y² - y - 6 = 0
(y - 3)(y + 2) = 0
Thus, y = -2 and 3.
We can calculate dy/dx at each point:
At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.
At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.
The answer should be n=-8
Answer:
The chance of getting exactly 3 hits is = 0.20
Step-by-step explanation:
P.S - The exact question is -
As given,
F(x) = 0 , x < 1
0.30 , 1 ≤ x < 2
0.56 , 2 ≤ x < 3
0.76 , 3 ≤ x < 4
0.9 , 4 ≤ x < 5
1 , 5 ≤ x
Now,
f(x) = 0.30 , x = 1
0.56 - 0.30 = 0.26 , x = 2
0.76 - 0.56 = 0.20 , x=3
0.9 - 0.76 = 0.14 , x = 4
1 - 0.9 = 0.1 , x = 5
0, otherwise
Now,
The chance of getting exactly 3 hits is = f(x = 3) = 0.20
Answer:
what do you need help with??