First you would find that not all the units are the same in this problem, so you convert yards to feet. So 4 yards = 12 feet.
The proportion you would make would be x/12 = 2/1
Answer:
a) weight of the car = 2816,1 lbs
b) 2773 lbs
Step-by-step explanation:
The equilibrium force is 490 lbs. That force keep the car at rest, then
∑ Fy = 0 and ∑Fx = 0
Forces acting on the car:
The external force 490 lbs
weight of the car uknown
Normal force
sin∠10° = 0,174
cos∠10° = 0.985
∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0
mg*0,174= 490
mg = 490 / 0,174
mg = 2816,1 lbs
weight of the car = 2816,1 lbs
The Normal force
mg*cos10° - N = 0 2816,1 * 0,985 = N
N = 2773 lbs
Then equal force in magnitude and in opposite direction will car exets on the driveway
If it is marked down 25% and 25% equals 25/100 then you simply take 39.59 x 25/100
39.59 x 25/100 = 9.90
and then you subtract that from the original price
39.59 - 9.90 = $29.69
after it is marked down, the price is $29.69
The answer is actually 1.571
First, I'm going to separate factor the expression inside of the square root.
sqrt[ (2/18) * (x^5) ]
sqrt[ (1/9) * (x^5) ]
We can take the square root of 1/9 easily, because 1 and 9 are both perfect squares. The square root of 1/9 is 1/3.
Looking at the x^5, we can separate it into x^2 * x^2 * x^1. The square root of x^2 is x. So, we now also have an x^2 on the outside because there are two x^2s in our expanded form.
ANSWER: (x^2 * sqrt(x)) / 3
(Option 1)
Hope this helps!