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1 year ago

5

Frank works at a convenience store. He earns 7.50 per hour when he works during the day. He earns 12.50 per hour when he works a

t night. He wants to San at least 300 per week. Which graph best represents this situation?

2 answers:

fredd [130]1 year ago

6 0

Answer:

7.50x + 12.50y = 300

Step-by-step explanation:

Anna71 [15]1 year ago

4 0

7.50x+12.50y=300 hope this helps

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Which criterion can be used to prove ABC and ADC are congruent?

Darya [45]

Answer:

D. ASA

Step-by-step explanation:

In triangles ABC and ADC,

Angles BCA and DAC are congruent (from the diagram);
Angles BAC and DCA are congruent (from the diagram);
AC is congruent AC (by reflexive property).

So, the triangles ABC and CDA are congruent by ASA postulate.

ASA (Angle-Side-Angle) postulate states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the triangles are congruent.

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2 years ago

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Larry's small business has $60,000 dollars in its account and makes automatic

son4ous [18]

Answer:

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Step-by-step explanation:

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2 years ago

Under what condition is √x > √25?

kvasek [131]

$\sqrt x > \sqrt{25} \qquad( x\geq 0)\\\sqrt x > 5\\x > 25$

When $x > 25$ .

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1 year ago

The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of <em>y</em> as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |<em>x </em>| ≤ 605.

⇒ -605 ≤ <em>x</em> ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0

2 years ago

The graph of the parent function y = x cubed is horizontally stretched by a factor of One-fifth and reflected over the y-axis. W

sasho [114]

Answer: OPTION D.

Step-by-step explanation:

Below are some transformations for a function f(x):

If $-f(x)$ , then the function is reflected over the x-axis.

If $f(-x)$ , then the function is reflected over the y-axis.

If $f(bx)$ and $b>1$ , then the function is horizontally compressed.

If $f(bx)$ and $0 < b$ , then the function is horizontally stretched.

In this case you know that the parent function is:

$y=x^3$

According to the information given in the exercise, the parent function IS horizontally stretched by a factor of $\frac{1}{5}$ and it is also reflected over the y-axis.

Therefore, based on the transformations explained before, you can notice that the transformation is:

$f(-bx)$

Where $0 < b$

Therefore, the equation of the transformed function is:

$y=(-\frac{1}{5}x)^ 3$

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2 years ago

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