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1 year ago

What is the product of (2p 7)(3p2 4p – 3)? 6p3 29p2 – 34p 21 6p3 29p2 – 22p 21 6p3 29p2 22p – 21 6p3 29p2 34p – 21

1 answer:

4 0

The product of the two provided equations, obtained by multiplying each term of the first equation from the second one, is 6p³+29p²+22p-21.

<h3>What is the product of two equations?</h3>

To multiply the two equation, each term of the first equation is multiples from the second term.

The first equation provided in the form of binomial as,

$2p+ 7$

The second equation provided in the form of quadratic equation as,

$3p^2 +4p-3$

The product of these two equations are,

$P=(2p+7)\times (3p^2 +4p-3)\\P=6p^3+8p^2-6p+21p^2+28p-21$

Arrange the equation with the same power terms,

$P=6p^3+8p^2+21p^2-6p+28p-21\\P=6p^3+29p^2+22p-21$

Hence, the product of the two provided equations, obtained by multiplying each term of the first equation from the second one, is 6p³+29p²+22p-21.

Learn more about the multiplication of two equation here;

brainly.com/question/69383

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Use this formula to find all the solutions of the equation. (Round terms to four decimal places)

Misha Larkins [42]

I might be misreading something here but if:

x^5+243=0 subtract 243 from both sides

x^5=-243 raise both sides to the 1/5 power (or take the fifth root of both sides)

x=-3

So there is only one solution, x=-3

3 0

3 years ago

Which formula can be used to describe the sequence below?

saul85 [17]

An=A1+(n-1)d

A2=-8+(2-1)3

A2=-8+3=-5

5 0

2 years ago

PLEASE HELP ME!!

Step2247 [10]

Answer:

A = $10,441.68

A = P + I where

P (principal) = $10,400.00

I (interest) = $41.68

Step-by-step explanation:

First, convert R as a percent to r as a decimal

r = R/100

r = 0.02/100

r = 0.0002 rate per year,

Then solve the equation for A

A = P(1 + r/n)nt

A = 10,400.00(1 + 0.0002/2)(2)(20)

A = 10,400.00(1 + 0.0001)(40)

A = $10,441.68

Summary:

The total amount accrued, principal plus interest, with compound interest on a principal of $10,400.00 at a rate of 0.02% per year compounded 2 times per year over 20 years is $10,441.68.

8 0

2 years ago

You are a landlord, and your tenant complains that you are in violation of the ADA because your wheelchair ramp is too steep. An

Savatey [412]

Answer:

Not justified

Step-by-step explanation:

ADA requirements are for a slope of 1 in 12 or less, an 8.3% grade, or an angle of 4.8° (actually, 4.764° when rounded to 3 decimal places). The ramp angle found by the assessor is compliant.

The tenant complaint does not seem justified.

3 0

2 years ago

A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of <em>z</em> for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

2 years ago