There are few differences in Florida plants as fall arrives. What differences might you see in the seeds of Florida plants?
1 answer:
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Answer: Choice C
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Explanation:
There are four marked points on the line.
Each point is of the form (x,y)
- The first or left most point is (0,1)
- The second point is (2,2)
- The third is (4,3)
- The fourth is (6,4)
Each of these points is then listed in the table format as shown above.
There are infinitely many other points on the line; however, we only select a few of them to make the table (or else we'd be here all day).
Extra side notes:
- The slope of this line is m = 1/2 = 0.5
- The y intercept is 1 located at (0,1)
- The equation of this line is y = 0.5x+1
Answer:
So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.
Step-by-step explanation:
In this data we have
Mean= u = 18
X= 38
Standard deviation = s= 6
1) We formulate the null and alternate hypothesis as
H0: u = 18 against Ha : u > 18 One tailed test .
2) The significance level alpha = ∝= 0.05 and Z alpha has a value ± 1.645 for one tailed test.
3)The test statistics used is
Z= X- u / s
z= 38-18/6= 3.333
4) The calculated value of z = 3.33 is greater than the z∝ = 1.645
5) So we reject the null hypothesis and accept the alternate hypothesis that rats learn slower with sound.
First we set the criteria for determining the true of value of the variable. That whether the rats learn in less or more than 18 trials.
Then we find the value of z for the given significance value given and the test about to be checked.
Then the test statistic is determined and calculated.
Then both value of z and z alpha re compared. If the test statistics falls in the rejection region reject the null hypothesis and conclude alternate hypothesis is true.
The figure shows that the calulated z value lies outside the given z values
