The height of the parallelogram that has an area of (32 + √2) ft² and base of (4+√2) ft is 9(7 + 2√2) / 7 ft
<h3>How to calculate area of a parallelogram?</h3>
area of parallelogram = bh
where
Therefore,
area = (32 + √2) ft²
base = (4+√2) ft
Therefore,
area of a parallelogram = bh
(32 + √2) = (4+√2)h
divide both sides by (4+√2)
h = (32 + √2) / (4+√2)
h = (32 + √2) / (4+√2) × (4-√2) / (4-√2)
h = (32 + √2) (4-√2) / 16 - 4√2 + 4√2 - 2
h = 128 + 32√2 + 4√2 - 2 / 14
h = 126 + 36√2 / 14 ft
h = 18(7 + 2√2) / 14 ft
h = 9(7 + 2√2) / 7 ft
learn more on parallelogram here: brainly.com/question/8377736
