The mass of NaCl that reacted with the F₂ gas at 290 K and 1.5 atm is 132.6 g
<h3>Ideal gas law Equation & Stoichiometry</h3>
From the question, we are to determine the mass of NaCl that reacted with F₂
First, we will determine the number of moles of F₂ that reacted
From the ideal gas law equation, we have that
Where n is the number of moles
P is the pressure
V is the volume
R is the gas constant (R = 0.08206 L.atm.mol⁻¹.K⁻¹)
and T is the temperature in Kelvin
From the given information,
V = 18.0 L
T = 290 K
P = 1.5 atm
Putting the parameters into the equation, we get
n = 1.1346 moles
Now, we will determine the number of moles of NaCl that reacted with this amount of F₂ gas
From the given balaced chemical equation,
F₂ + 2NaCl → Cl₂ + 2NaF
This means, 1 mole of F₂ gas reacts completely with 2 moles of NaCl
Since
1 mole of F₂ gas reacts completely with 2 moles of NaCl
Then,
1.1346 moles of F₂ gas will react completely with 2×1.1346 moles of NaCl
2×1.1346 = 2.2692 moles
This is the number moles of NaCl that reacted
Now, for the mass of NaCl that reacted
From the formula,
Mass = Number of moles × Molar mass
Molar mass of NaCl = 58.44 g/mol
Mass of NaCl that reacted = 2.2692 × 58.44
Mass of NaCl that reacted = 132.6 g
Hence, the mass of NaCl that reacted with the F₂ gas at 290 K and 1.5 atm is 132.6 g
Part 2
To determine the mass of sodium chloride that can react with the same volume of fluorine gas at STP, follow the steps as shown above. But, we will change temperature and pressure to the standard temperature and pressure values. The standard temperature and pressure values are 273.15 K and 1.0 atm respectively.
Afterwards, we will then calculate the mass of sodium chloride needed by using the calculated number of moles and the formula as shown above.
Learn more on Ideal gas law equation & Stoichiometry here: brainly.com/question/15371174
brainly.com/question/8802422