Because then it would be easier to get an answer for a problem
Answer:
1. a) (1-1) (1-2) (1-3) (2-1) (2-2) (3-1)
2. a) (5-1) (5-2) (5-3) (5-4) (5-5) (5-6)
3. d) (1-3) (2-3) (3-1) (3-2) (3-4) (3-5) (3-6) (4-3) (5-3) (6-3)
Step-by-step explanation:
1. added the numbers in the parenthesis and A had all of the sums less than 5
2. A had all the 5s in the first spot
3. D had the 3s in each parenthesis
Step-by-step explanation:
3x+18+2x-5= -2x+-2+10
combining like terms
3x+2x+2x=5-2+10-18
7x=-5
x=-5/7
We need Pythagoras theorem here
a^2+b^2 = c^2
a, b = legs of a right-triangle
c = length of hypotenuse
Let S=shorter leg, in cm, then longer leg=S+2 cm
use Pythagoras theorem
S^2+(S+2)^2 = (10 cm)^2
expand (S+2)^2
S^2 + S^2+4S+4 = 100 cm^2 [collect terms and isolate]
2S^2+4S = 100-4 = 96 cm^2
simplify and form standard form of quadratic
S^2+2S-48=0
Solve by factoring
(S+8)(S-6) = 0 means (S+8)=0, S=-8
or (S-6)=0, S=6
Reject nengative root, so
Shorter leg = 6 cm
Longer leg = 6+2 cm = 8 cm
Hypotenuse (given) = 10 cm
Answer:
.5, sqrt 14, 4
Step-by-step explanation:
.5, 3.7416, 4
