Let the solutions be a and b.
a = -2; b = -10
a + b = -2 + (-10) = -12
ab = (-2)(-10) = 20
(x - a)(x - b) = 0
(x - (-2))(x - (-10)) = 0
(x + 2)(x + 10) = 0
x^2 + 10x + 2x + 20 = 0
x^2 + 12x + 20 = 0
-h = 12
h = -12
4k = 20
k = 5
Jack is 10 blocks away from the school
Answer:
It is 50 cm squared hxb/2=a
Answer:
B
Step-by-step explanation:
x^3 + 2x^2 - 9x - 18 = x^2(x + 2) - 9(x + 2) = (x + 2)*(x^2 - 9)
(x + 2)/(x + 2)(x^2 - 9) = 1 / (x^2 - 9)
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1/(x^2 - 9) * (x^2 - 9)/(3x + 1) = 1/(3x + 1)
Yes B is correct.
The answer to this problem is neither. To find this you would just plug in each ordered pair into the equation for the x and y values. Then you would compare if they are equal