Question

If 0.5 L of a gas is cooled from 22°C to 4°C, what is the new volume of the gas?

Answer 1

Answer:

B

Explanation:

From charles' law,

$v \alpha t$

where v is volume and t is absolute temperature

• $\frac{v1}{t1} = \frac{v2}{t2}$
• $v1 = 0.5l \\ t1 = (22 + 273 )k\\ t2 = (4 + 273)k \\ t1 = 295k \\ t2 = 277k \\ \frac{0.5}{295} = \frac{v2}{277} \\ v2 = 277 \times \frac{0.5}{295} = 0.47l$
• Hence that's it