1a) f(x) = I x+2 I. This is a piece-wise graph ( V form) x = 0 →f(x) =2 (intercept y-axis) x = -2→f(x) = 0 (intercept x-axis) x = -3→f(x) = 1 (don't forget this is in absolute numbers) x = -4→f(x) = 2 (don't forget this is in absolute numbers) Now you can graph the V graph
1b) Translation: x to shift (-3) units and y remains the same, then f(x-3) = I x - 3 + 2 I = I x-1 I the V graph will shift one unit to the right, keeping the same y. Proof: f(x) = I x-1 I . Intercept x-axis when I x-1 I = 0, so x= 1
