Perimeter of a rectangle:
P=2I+2W=2(I+w)
But if the length and width of a rectangle are both double, then we would have:
Length=2I
width=2w
Therefore, its perimeter would be:
P=2(2I+2w)=4(I+w)
the old perimeter was P=2(I+w) and the new perimeter is P=4(I+w)=2[2(l+w)]
There the perimeter is twice as great.
Answer: C) the perimeter is twice as great.
Answer:
Step-by-step explanation:
Theorm-The Fundamental Theorem of Algebra: If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.
Let's verify that the Fundamental Theorem of Algebra holds for quadratic polynomials.
A quadratic polynomial is a second degree polynomial. According to the Fundamental Theorem of Algebra, the quadratic set = 0 has exactly two roots.
As we have seen, factoring a quadratic equation will result in one of three possible situations.
graph 1
The quadratic may have 2 distinct real roots. This graph crosses the
x-axis in two locations. These graphs may open upward or downward.
graph 2
It may appear that the quadratic has only one real root. But, it actually has one repeated root. This graph is tangent to the x-axis in one location (touching once).
graph 3
The quadratic may have two non-real complex roots called a conjugate pair. This graph will not cross or touch the x-axis, but it will have two roots.
Problem: 4+x=15
- Subtract 4 from both sides
4+x-4=15-4
- Refine
x = 11
Answer:
22
Step-by-step explanation:
x-1 is a midsegment.
According to the Triangle midsegment theorem, x-1 is half of the third side (42)
x-1 = 42/2
x-1 = 21
x= 22
or
2x-2=42
2x=44
x=22
Hope this helps!
