What is the lateral surface area of this right pyramid with a square base?

Mathematics

1 answer:

Brums [2.3K]1 year ago

7 0

Answer:

The lateral surface area of a square pyramid is the sum of the areas of the side faces only, whereas the surface area is the lateral area + area of the base. The lateral area of a square pyramid = 2al (or) 2a√[(a 2 /4) + h 2]. To get the surface area, we need to add the area of the base (which is a 2) to each of these formulas.The surface area of a square pyramid = a 2 + 2al (or) a 2 + 2a[(a 2 /4) + h 2]. where, a = Length of the base (square) l = slant height; h = height of the pyramid.

Step-by-step explanation:

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Solve the following simultaneous linear equations.<br>2x + y = 5<br>4x – 3y = -10

Jet001 [13]

Answer:

(1/2,4)

Step-by-step explanation:

First, determine y in first equation: 2x+y=5 or y=5-2x

replace value of y determined in first equation (5-2x) into 2nd equation

4x-3(5-2x)=-10

4x-15+6x=10

10x=5

x=1/2

put value of x into either equation to solve for y so

2(1/2)+y=5

1+y=5

y=4

answer: x=1/2, y=4

check answer by substituting x and y into either equation:

4x-3y=-10

4(1/2)-3(4)=-10

2-12=-10

-10=-10

2x+y=5

2(1/2)+4=5

1+4=5

5=5

7 0

2 years ago

Which number gives you an irrational product when you multiply it by 2

soldi70 [24.7K]

<h2>Explanation:</h2><h2></h2>

An irrational number is a number that can't be written as a simple fraction while a rational number is a number that can be written as the ratio of two integers, that is, as a simple fraction. So in this case we have the number 2 which is ration, and we can multiply it by an irrational number $n$ such that the product is an irrational number. So any irrational number will meet our requirement because the product of any rational number and an irrational number will lead to an irrational number. For instance:

$\bullet \ 2\sqrt{2} \\ \\ 2 \ is \ rational \\ \\ \sqrt{2} \ is \ irrational \\ \\ 2\sqrt{2} \ is \ irrational \\ \\ \\ \bullet \ 2\pi \\ \\ 2 \ is \ rational \\ \\ \pi \ is \ irrational \\ \\ 2\pi \ is \ irrational$