Times the price of the model cars to the amount bought.
$15×6= 90.
Lea paid 90 dollars for the model cars.
Now, multiply the price of the paint to the amount bought.
$11×4= 44.
Lea paid 44 dollars for the paint.
Add both together. 90+44= 134.
Therefore, Lea paid $134 for the model cars and paint all together.
hope this helps!
100+16=116 is the right answer
Your question is incomplete, but I am guessing that it reads something like:
“Diego has run 4/5 of a race distance. He has run 7 2/3 miles. How long is the race? Or “how many miles does he have left?”
How long is the race? = 9 7/12 miles
4/5x = 7 2/3
4/5x = 23/3
x = 23/3 • 5/4
x = 115/12
x = 9.58333
x = 9 7/12 miles
How many miles does he have left? = 1 1/12 miles
1/5 • 115/12 = 115/60 = 1.916666
= 1 55/60 = 1 11/12 miles
Let me know if I didn’t guess your question correctly and I will try to help more.
Answer:
(a) 12.96 ft²
(b) 21.5 in²
Step-by-step explanation:
(a) For the first diagram
Area of the shaded region (A) = Area of Tripezium- area of circle
A = [1/2(a+b)h]-[πr²]............... Equation 1
Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.
From the diagram,
Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.
Constant: π = 3.14
Substitute these values into equation 1
A = [12(15+6)/2]-(3.14×6²)
A = 126-113.04
A = 12.96 ft²
(b) For the second diagram,
Area of the shaded region (A') = Area of square- area of circle
A' = (L²)-(πr²)............. Equation 2
Where L = lenght of one side of the square, r = radius of the circle
From the diagram,
Given: L = 2r = (2×5) = 10 in, r = 5 in
Substitute these values into equation 2
A' = (10²)-(3.14×5²)
A' = 100-78.5
A = 21.5 in²
Answer:
-4, 4
Step-by-step explanation:
it seems the most reasonable answer since the dot is not super close to the 6, 6 and it isnt close enough to be 1, 5 or 5, 1 so the answer must be -4, 4
