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2 years ago

() Which of the following fractions is the largest? A.5/81 B.75/81 C.10/9 D.11/9

Mathematics

2 answers:

Georgia [21]2 years ago

8 0

Answer:

D. 11/9

Step-by-step explanation:

Which of the following fractions is the largest?

A. 5/81

B. 75/81

C. 10/9

D. 11/9

To make things easier, convert the fractions to decimals:

A. 5/81 = 0.062

B. 75/81 = 0.93

C. 10/9 = 1.11

D. 11/9 = 1.22

As we can see, 11/9 or 1.22, is the largest of all the values.

Hope this helps!

harkovskaia [24]2 years ago

8 0

<h3>Step 1. Make the denominators of the fractions equivalent:</h3>

Given set of fractions: 5/81, 75/81, 10/9, 11/9

To make the denominators of the given fractions equivalent, we need to determine the LCM of the denominators. Clearly, the denominators of the set of fractions are 81, 81, 9, and 9 respectively.

81 ⇔ 81, 162, 243...
9 ⇔ 9, 18, 27, 36, 45, 54, 63, 72, 81, 90....

LCM = 81 (81 × 1 = 81 and 9 × 9 = 81)

Multiply the denominators such that the denominator is equivalent to 81. Keep in mind that if we are multiplying a number (x), the numerator must be multiplied by the same number (x) .

⇒ 5/81, 75/81, 10/9, 11/9

⇒ (5 × 1)/(81 × 1), (75 × 1)/(81 × 1), (10 × 9)/(9 × 9), (11 × 9)/(9 × 9)

⇒ (5)/(81), (75)/(81), (90)/(81), (99)/(81)

⇒ 5/<u>81</u>, 75/<u>81</u>, 90/<u>81</u>, 99/<u>81</u>

<h3>Step 2. Compare the fractions in the given set:</h3>

Since 99 > 90 > 75 > 5, we can tell that 99/81 is the largest as:

5/81 (5/81) < 75/81 (75/81) < 90/81 (10/9) < 99/81 (11/9)

Therefore, 11/9 is the largest fraction in the set.

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7 0

2 years ago

So I kinda forgot how to do this *nervous laughter* um help

natali 33 [55]

1) value of x =60

2) value of x = 3

Step-by-step explanation:

We need to use cross products to solve the proportions of x.

$1.\,\, \frac{3}{5}= \frac{x}{100}$

Solving:

$\frac{3}{5}= \frac{x}{100}\\Cross\,\,multiply\,\,:\\5x=3*100\\5x=300\\x=\frac{300}{5}\\x=60$

So, value of x =60

$2.\,\,\frac{x}{8}=\frac{7.5}{20}$

$\frac{x}{8}=\frac{7.5}{20} \\20x=7.5*8\\20x=60\\x=\frac{60}{20}\\ x=3$

So, value of x = 3

Keywords: Ratio and Proportions

Learn more about Ratio and Proportions at:

#learnwithBrainly

7 0

2 years ago

When is it helpful to estimate quotients?

pantera1 [17]

It is helpful to estimate quotients when the number is very big.

3 0

2 years ago

X-26 over -9= 5 please help quick

nexus9112 [7]

Answer:

x = -19

Step-by-step explanation:

$\frac{x-26}{-9}=5$

Multiply both sides of the equation by -9.

$\frac{\left(x-26\right)\left(-9\right)}{-9}=5\left(-9\right)$

x - 26 = -45

Add 26 to both sides.

x - 26 + 26 = -45 + 26

x = -19

6 0

1 year ago

A certain bookstore chain has two stores, one in San Francisco and one in Los Angeles. It stocks three kinds of books: hardcover

riadik2000 [5.3K]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

$\left[\begin{array}{cccc}T&H&S&P\\S&600&1300&2000\\L&400&300&400\end{array}\right]$ = A.

In the above matrix A, the columns refers the three type of books and the rows refers the from which stores the books are been sold.

The numbers represents the corresponding sales in the month of January.

The sale is same for the 6 months.

Hence, 6A = $\left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right]$ . This matrix 6A represents the total sales over the 6 months.

(b)

If we denote the books in stock at the starting of January by B, then

B = $\left[\begin{array}{cccc}T&H&S&P\\S&1000&3000&6000\\L&1000&6000&3000\end{array}\right]$ .

Each month, the chain restocked the stores from its warehouse by shipping 500 hardcover, 1,400 softcover, and 1,400 plastic books to San Francisco and 500 hardcover, 500 softcover, and 500 plastic books to Los Angeles.

If we represent the amount restocked books at the end of each month by another matrix C, then

C = $\left[\begin{array}{cccc}T&H&S&P\\S&500&1400&1400\\L&500&500&500\end{array}\right]$ .

This restocking will be done for 5 times before the end of June.

If there would be no sale, then the stock would be

B + 5C = $\left[\begin{array}{cccc}T&H&S&P\\S&1000+2500&3000+7000&6000+7000\\L&1000+2500&6000+2500&3000+2500\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right]$ .

Since, the total sale is given by 6A, at the end of June, the inventory in each store can be shown as following,

B+5C-6A $\left[\begin{array}{cccc}T&H&S&P\\S&3500&10000&13000\\L&3500&8500&5500\end{array}\right] - \left[\begin{array}{cccc}T&H&S&P\\S&3600&7800&12000\\L&2400&1800&2400\end{array}\right] \\= \left[\begin{array}{cccc}T&H&S&P\\S&-100&2200&1000\\L&1100&6700&3100\end{array}\right]$

6 0

2 years ago