Vertex form: y = a(x - h)² + k
h = 2
k = -1
y = 0
x = 5
0 = a(5 - 2)² - 1
0 = 9a - 1
a = 1/9
Answer: A and B only
Step-by-step explanation:
In function, for one value of x there must be only one value of y.
can you make the pic little more clear if you can :)
Part A:
Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4
The perimeter of the square is given by 4(x + 4) = 4x + 16
The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12
For the perimeters to be the same
4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2
The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.
Part B:
The area of the square is given by
The area of the rectangle is given by 2(3x + 4) = 6x + 8
For the areas to be the same
Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
<span>reducible.
hope this helps</span>