Answer:
the moluculer formula is the answer
Explanation:
Answer:
The mass of the element is 141.03701 amu
Explanation:
The catch here is that it notes a " newly found element. " Otherwise you could just refer to the average atomic mass of the element in the periodic table, and receive your solution in a much faster way.
The first isotope has an atomic mass of 139.905 amu, and a respective percent abundance of 37.25%. The second isotope has an atomic mass of 141.709 amu, and the remaining percent abundance, 100% - 37.25% = 62.75% ( given ). We can calculate the mass of the unknown element by associating each percentage with the mass of their respective isotope, over 100%.
Mass = ( ( 139.905 amu )( 37.25% ) + ( 141.709 amu )( 62.75% ) )/ 100,
Mass = ( ( 5211.46125 ) + ( 8892.23975 ) ) / 100,
Mass = ( 14103.701 ) / 100 = 141.03701 amu
H2Se is the acid as it is donating H+ to H2O and forming SeH- (which is conjugate base).
H2O is the base since it’s receiving H+ from H2Se to form H3O+ (which is the conjugate acid)
Se is in the same group as O but is in different period which means Se has higher radius compred to O. this led to H-O bond being stronger than H-Se bond and H-Se bond which in turn makes it easier for H2Se to donate H to H2O