D is the best answer
(I am just using my common sense)
Hope I helped :)
Answer:
Nowadays energy generation heavily relies on fossil fuels causing environmental challenges. The global biofuels supply has increased by a factor of 8% since 2010, but only comprises 4% of the world’s transport fuels in 2015. The development of next generation of biofuel becomes increasingly important due to the depletion of fossil fuels and in the meantime to overcome challenges for current biofuels production – high cost and low efficiency. The biological production of lipid droplets in oleaginous microorganisms like microalgae, yeast, fungi, and bacteria becomes a promising path to the next generation of biofuels.
The lipid droplet (LD) is a cellular organelle that consists of a neutral lipid, mainly of triacylglycerols (TAGs) and cholesteryl esters, cored with a monolayer-phospholipid membrane and associated proteins. Lipid droplets widely exist in both prokaryotic and eukaryotic cells, could be collected and extracted for biofuel manufacturing. However, this technology is now limited in lab research. Methods to improve the lipid droplet production in oleaginous microorganisms, biomass pretreatment, lipid droplet extraction, industrial scalability are still under development. The experience of liposome manufacturing provides us a solid ground for lipid droplet studies and helps our clients move to a further step of new biofuel development.
Explanation:
https://www.creative-biostructure.com/Lipid-Droplets-Biofuel-Supply-626.htm
There are 27 x 10⁷ cells in total for the given conditions of cell culture.
Since it is given that the cell culture contains 3 x 10⁵ cells per ml and there are 12 culture flasks in total. It is also given that each of the culture flask holds 75 ml of culture.
Therefore, to calculate the total capacity of the flasks the total number of flasks should be multiplied with the individual capacity of a flask:-
75 x 12 = 900 ml
Now, in order to calculate the total number of cells in the given culture., the total capacity of the flasks i.e. 900 ml should be multiplied with 3 x 10⁵ cells per ml in the following manner:-
900 x (3 x 10⁵) = 2700 x 10⁵ = 27 x 10⁷ cells
To learn more about cell culture here
brainly.com/question/1005896
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The radius is on the outside, or lateral side, of the elbow. It connects to the thumb side of the wrist. The radius is bigger and longer than the ulna which is on the inside, or medial side, of the forearm closest to the body.
Answer:
- hyperpolarization
- depolarization
- hyperpolarization
- depolarization
- hyperpolarization
- depolarization
- depolarization
Explanation:
The resting membrane potential is balanced by ion leakage and ion pumping, to get an electrical signal started the membrane potential has to lose its balance. This starts with a membrane channel opening for Na+ since Na+ concentration is higher outside the cell, ions will rush into the cell. This will change the relative voltage inside the cell. The resting potential has a voltage of -70 mV, the sodium cation entering the cell cause it to become less negative. <em>This is known as depolarization.</em>
The concentration gradient for Na+ will continue to enter the cell making the voltage to become positive reaching +30 mV. At the same time, this happens, other voltage-gated channels are also opening, a concentration gradient acts on K+, as well, as it leaves the cell, it takes a positive charge with it making the membrane potential to move back to its resting voltage of -70 mV. <em>This is called repolarization. </em>
For potassium ions to reach equilibrium the membrane voltage needs to be below -70 mV, this leads to a period of <em>hyperpolarization</em> that occurs while the K+ channels are open.
I annexed an image that illustrates this action potential process.
<em>Considering the information given during depolarization there's an increase in the number of sodium leak channels (7) making the inside of the cell more positive (2) increase in the membrane potential (4), this also implies a decrease in the extracellular concentration of potassium (6)</em>
<em>Meanwhile, during hyperpolarization an increase in the extracellular concentration of potassium (3) decreases the membrane potential (1) making the inside of the cell more negative (5).</em>
I hope you find this information useful and interesting! Good luck!<em>
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