Please help with this question.

Mathematics

2 answers:

laila [671]1 year ago

6 0

Answer:

A. Perpendicular Bisector Theorem :)

If a point is the perpendicular bisector of a segment, it splits the segment equally in half, meaning that the endpoints are equidistant from the bisector!

BartSMP [9]1 year ago

3 0

Answer:

I think A is the best answer

Step-by-step explanation:

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Given that the two triangles are similar, solve for x if AU = 20x + 108, UB = 273, BC = 703, UV = 444, AV = 372 and AC = 589.

Damm [24]

The answer:
<span>the two triangles are similar
in addition, the line UV is parallel to line BC, so we can use the theorem of Thales for proving the following ratios:

AV /AC = AU/ AB= UV/ BC
372/589=20x +80 / AB = 444 / 703

</span>so we get (372/589) AB - 80 = 20x, and x = ( (372/589) AB - 80 ) / 20

exact value of x depends on the value of AB

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2 years ago

Please help with number 10

Flura [38]

Answer:

see below for a drawing
the area of one of the trapezoids is 20 units²

Step-by-step explanation:

No direction or other information about the desired parallelogram is given here, so we drew one arbitrarily. Likewise for the segment cutting it in half. It is convenient to have the bases of the trapezoids be the sides of the parallelogram that are 5 units apart.

The area of one trapezoid is ...

A = (1/2)(b1 +b2)h = (1/2)(3+5)·5 = 20 . . . . square units

The sum of the trapezoid base lengths is necessarily the length of the base of the parallelogram, so the area of the trapezoid is necessarily 1/2 the area of the parallelogram. (The area is necessarily half the area of the parallelogram also because the problem has us divide the parallelogram into two identical parts.)