3)
1 answer:
Answer:
2500 pence (C = 2500)
Step-by-step explanation:
From the given information, t is the number of texts so essentially you will plug in the number of texts provided (150) in the place of the variable t.
Apply the same thing to minutes, plug in the number of minutes (50) in the place of the variable m.
Now multiply the substitutes with the co-efficient. (10*150=1500 & 20*50=1000)
Add the addends
C = 2500
You might be interested in
(a)
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
= y
Answer for (a):
=
(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y:
Answer for (b):
= 
(c)
replace all t's in the equation with
= 
=
= 
= 
Answer for (c):
= 
(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1
(e)
h(g(t)) = 8t - 1
y = 8 t - 1
t = 8y - 1
t + 1 = 8y
= y
Answer for (e): inverse of h(g(t)) =
The inverse is when you swap the variables and solve for y.
g(t) = 2t - 1 (Note: g(t) represents y)
rewrite as: y = 2t - 1
swap the variables: t = 2y - 1
solve for y: t + 1 = 2y
Answer for (a):
(b)
Same steps as part (a) above:
h(t) = 4t + 3
rewrite as: y = 4t + 3
swap the variables: t = 4y + 3
solve for y:
Answer for (b):
(c)
replace all t's in the
=
Answer for (c):
(d)
h(g(t)) = h(2t - 1) = 4(2t - 1) + 3 = 8t - 4 + 3 = 8t - 1
Answer for (d): h(g(t)) = 8t - 1
(e)
h(g(t)) = 8t - 1
y = 8 t - 1
t = 8y - 1
t + 1 = 8y
Answer for (e): inverse of h(g(t)) =