36.4+(-68.15) how do I compute this?
1 answer:
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Part A
Given that
Then,
For
, then
Thus,
For
, we have
Part B
Recall that from part A,
Now, at initial position, t = 0 and
, thus we have
and when the velocity drops to half its value,
and 
Thus,
Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by
Given that
Then,
For
Thus,
For
Part B
Recall that from part A,
Now, at initial position, t = 0 and
and when the velocity drops to half its value,
Thus,
Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by
Answer:
x=2.65
Step-by-step explanation:
First, we need to figure out how much the length of the sides is changing between the equations. In this case it is changing by a factor of 2.5. Now we need to work backwards. First use this equation:
This is because whatever the length of the side with x is, will be 14/2.5. So divide both sides by 2.5:
Next, add 5 to both sides:
Then divide both sides by 4: