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1 year ago

PLS HELP WILL MARK YOU BRAINLIEST! NO FAKE ANSWERS! Find the mode of the data

Mathematics

2 answers:

rewona [7]1 year ago

7 0

Answer:

shoe size (US) 6

Step-by-step explanation:

Mode = most frequently occurring data value

From inspection of the table, we can see that the highest frequency (most number of women) is 20, so therefore the modal class of the data is shoe size (US) 6.

andre [41]1 year ago

6 0

Answer:

<u>Shoe Size (US) = 6</u>

Step-by-step explanation:

The mode of the data is the modal class with the highest frequency
It is 20, present in the 4th column
Its corresponds with the modal class : <u>Shoe Size (US) = 6</u>

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2 years ago

What are the solutions of x^2-2x+5=0

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2 years ago

The sum of three consecutive even numbers is 96. What is the smallest of the three numbers

lidiya [134]

The answer is 30.

First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.

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8 0

2 years ago

Customers arrivals at a checkout counter in a department store per hour have a Poisson distribution with parameter λ = 7. Calcul

IgorLugansk [536]

Answer:

(1)14.9% (2) 2.96% (3) 97.04%

Step-by-step explanation:

Formula for Poisson distribution: $P(k) = \frac{\lambda^ke^{-k}}{k!}$ where k is a number of guests coming in at a particular hour period.

(1) We can substitute k = 7 and $\lambda = 7$ into the formula:

$P(k=7) = \frac{7^7e^{-7}}{7!}$

$P(k=7) = \frac{823543*0.000911882}{5040} = 0.149 = 14.9\%$

(2)To calculate the probability of maximum 2 customers, we can add up the probability of 0, 1, and 2 customers coming in at a random hours

$P(k\leq2) = P(k=0)+P(k=1)+P(k=2)$

$P(k\leq2) = \frac{7^0e^{-7}}{0!} + \frac{7^1e^{-7}}{1!} + \frac{7^2e^{-7}}{2!}$

$P(k \leq 2) = \frac{0.000911882}{1} + \frac{7*0.000911882}{1} + \frac{49*0.000911882}{2}$

$P(k\leq2) = 0.000911882+0.006383174+0.022341108 \approx 0.0296=2.96\%$

(3) The probability of having at least 3 customers arriving at a random hour would be the probability of having more than 2 customers, which is the invert of probability of having no more than 2 customers. Therefore:

$P(k\geq 3) = P(k>2) = 1 - P(k\leq2) = 1 - 0.0296 = 0.9704 = 97.04\%$

4 0

2 years ago