Identify the polygon below as regular or irregular.

What is the value of x?<br><br> Enter your answer in the box.

Effectus [21]

Answer:

Step-by-step explanation:

Remark

These two angles are supplementary. They make up the horizontal line. Supplementary angles add to 180 degrees.

Equation

x + 134 = 180

Solution and Answer

x + 134 = 180 Subtract 134 from both sides

x + 134 - 134 = 180-134 Combine

Answer: x = 46

3 0

1 year ago

Please please please please

Alexeev081 [22]

Answer:

5cm wide, 10cm long.

Step-by-step explanation:

I came to this answer by looking for common factors between 50 and 5, and I found 10.

5cm + 5cm = 10cm, so it works.

To confirm this, I multiplied 5 and 10 and got 50cm (squared) which works.

3 0

2 years ago

Find two consecutive integers whose sum is the square of 7

Maksim231197 [3]

Answer:

Step-by-step explanation:

Two consecutive integers be x and (x+1)

x + x +1 = 7²

2x + 1 = 49

2x = 49 - 1

2x = 48

x = 48/2

x = 24

The consecutive integers are: 24,25

3 0

2 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

Matt started doing extra chores around the house and his allowance changed from $30 per week to $40 per week. What is the percen

slega [8]

Answer:

33.3%

Step-by-step explanation:

Let's say the percent change is x%. Then the equation is:

30 + x% * 30 = 40

Subtract 30 from both sides:

x% * 30 = 10

Divide by 30:

x% = 10/30 = 1/3

Remember that % simply means "out of 100", so:

x/100 = 1/3

Multiply both sides by 100:

x = (1/3) * 100 = 33.3%

3 0

2 years ago

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